A person standing at the edge of a seaside
cliff kicks a stone over the edge with a speed
of 12 m/s. The cliff is 41 m above the water’s
surface,
How long does it take for the stone to fall
to the water? The acceleration of gravity is
9.81 m/s
2
.
Answer in units of s
Norma is a unique SCHOOL SUBJECT.
physics
i did it so i could find it easier:P
But you made it impossible for a physics tutor to find your question easily.
To find the time it takes for the stone to fall to the water, we can use the equation of motion:
h = 1/2 * g * t^2
where:
h = height of the cliff (41 m)
g = acceleration due to gravity (9.81 m/s^2)
t = time taken for the stone to fall
We can rearrange this equation to solve for t:
t^2 = 2h / g
Substituting the given values:
t^2 = 2 * 41 m / 9.81 m/s^2
t^2 = 82 / 9.81
Now, taking the square root of both sides:
t = sqrt(82 / 9.81)
Using a calculator to evaluate this expression:
t ≈ 3.2 seconds
Therefore, it takes approximately 3.2 seconds for the stone to fall to the water.