What is the pressure in a 10.0-L cylinder filled with 0.470 mol of nitrogen gas at a temperature of 329 K?
PV = nRT
To find the pressure in the cylinder, we can use the ideal gas law equation, which is:
PV = nRT
Where:
P is the pressure,
V is the volume,
n is the number of moles,
R is the ideal gas constant, and
T is the temperature.
First, let's identify the values given in the question:
V = 10.0 L (volume)
n = 0.470 mol (number of moles)
T = 329 K (temperature)
The ideal gas constant, R, is a constant value that is usually given as:
R = 0.0821 L·atm/(mol·K)
Now, we can plug these values into the ideal gas law equation:
P * 10.0 L = 0.470 mol * (0.0821 L·atm/(mol·K)) * 329 K
Now, we can solve for P:
P = (0.470 mol * 0.0821 L·atm/(mol·K) * 329 K) / 10.0 L
P = 12.794 atm
Therefore, the pressure in the 10.0-L cylinder filled with 0.470 mol of nitrogen gas at a temperature of 329 K is approximately 12.794 atm.