How much does a 20ft x 10ft x 8ft swimming pool filled with water weight? Assume the water has a weight density of 62 lbs/ft3.
I know the answer is 99,200 pounds but how do I get that answer? Thanks<3
Volume x density.
In this case, that is all of your four numbers multiplied together. It is a constant-depth swimming pool.
Thank you so much! My teacher has NO idea how to teach us anything! I really appreciate your help! Thanks <3
D=m/v
M=d*vm=62*20*10*8
M=99200kg
Why did the swimming pool go on a diet? It wanted to make a splash without making a hefty weight!
To calculate the weight of the water in the swimming pool, you need to multiply the volume of the pool by the weight density of water.
First, find the volume of the pool:
20 ft x 10 ft x 8 ft = 1600 cubic feet
Then, multiply the volume by the weight density of water:
1600 ft³ x 62 lbs/ft³ = 99,200 pounds
So, a 20ft x 10ft x 8ft swimming pool filled with water would weigh about 99,200 pounds. Just remember, no diving into the math!
To calculate the weight of water in the swimming pool, you can use the formula:
Weight = Volume × Density
First, we need to calculate the volume of the pool:
Volume = Length × Width × Height
Given dimensions:
Length = 20ft
Width = 10ft
Height = 8ft
Volume = 20ft × 10ft × 8ft = 1600 ft^3
Next, we need to determine the weight density of the water, which is given as 62 lbs/ft^3.
Now, we can solve for the weight:
Weight = Volume × Density
Weight = 1600 ft^3 × 62 lbs/ft^3
Weight = 99,200 lbs
So, a 20ft x 10ft x 8ft swimming pool filled with water would weigh 99,200 pounds.
D=m/v
M=d*v
m=62*20*10*8
M=99200kg