Lexi and Marie had $250 altogether. After Lexi spent 2/5 of her money and Marie spent $40, they had the same amount of money left. how much money did Lexi have in the beginning ?
let x = amount of money of Lexi
let 250 - x = amount of amount of Marie
then set up the equation:
x - (2/5)x = 250 - x - 40
(3/5)x = 210 - x
(3/5)x + x = 210
(8/5)x = 210
x = 210*(5/8)
x = $ 131.25 (Lexi's money)
250 - x = 118.75 (Marie's money)
hope this helps~ :)
To solve this problem, we need to set up an equation based on the given information.
Let's assume Lexi had x dollars in the beginning. According to the problem, Marie had 250 - x dollars.
After Lexi spent 2/5 of her money, she had 3/5 of her money left. So, Lexi had (3/5)x dollars remaining.
Marie spent $40, so she had (250 - x) - 40 = (210 - x) dollars remaining.
According to the problem, Lexi and Marie had the same amount of money left, so we can set up an equation:
(3/5)x = (210 - x)
To solve for x, let's multiply both sides of the equation by 5 to eliminate the fraction:
5 * (3/5)x = 5 * (210 - x)
3x = 1050 - 5x
Next, let's add 5x to both sides of the equation and simplify:
3x + 5x = 1050
8x = 1050
Now, divide both sides of the equation by 8:
x = 1050 / 8
x = 131.25
Therefore, Lexi had $131.25 in the beginning.