An isotope of Glopenium disintegrates according to the formula
A(t) = Ao2^-0.0345t where Ao is the initial mass of the substance and t is the time in years. If there are 2 milligrams of Glopenium now, find the number of milligrams that will be left after 35 years. Your answer should be correct to the nearest thousandth of a milligram.
You have the formula, what's the problem?
A(35) = 2 * 2^-(0.0345*35)