as a baseball player strikes the ball with his batt the 1kg bat applies an average force of 250N on the .15kg baseball for .2 seconds. A) what is the force applied by the baseball on the bat? what is the acceleration of the baseball? C) what is the speed of the baseball at the end of the .2 seconds?
A) Action = Reaction
(Newton's third law)
B) F = M a
(Newton's second law)
C) Not enough information. You need to know the velocity of the pitched ball before it was hit. Whoever assigned the problem should know that
A) To determine the force applied by the baseball on the bat, we can use Newton's third law of motion, which states that every action has an equal and opposite reaction. Therefore, the force applied by the baseball on the bat is also 250N.
B) To find the acceleration of the baseball, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = ma). Rearranging the formula, we have acceleration (a) = force (F) / mass (m).
Given that the force is 250N and the mass of the baseball is 0.15kg, the acceleration can be calculated as follows:
a = 250N / 0.15kg
a ≈ 1666.67 m/s^2
Therefore, the acceleration of the baseball is approximately 1666.67 m/s^2.
C) To find the speed of the baseball at the end of the 0.2 seconds, we can use the equation for uniformly accelerated motion:
v = u + at
Where:
v = final velocity
u = initial velocity (assumed to be 0 as the question does not mention it explicitly)
a = acceleration (1666.67 m/s^2, as calculated in the previous step)
t = time (0.2 seconds)
Substituting these values into the equation:
v = 0 + (1666.67 m/s^2) * (0.2 s)
v ≈ 333.33 m/s
Therefore, the speed of the baseball at the end of the 0.2 seconds is approximately 333.33 m/s.
To answer these questions, we can apply Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration (F = m * a).
A) What is the force applied by the baseball on the bat?
According to Newton's third law of motion, for every action, there is an equal and opposite reaction. Therefore, the force applied by the baseball on the bat is equal in magnitude but opposite in direction to the force applied by the bat on the baseball. So, the force applied by the baseball on the bat is also 250N.
B) What is the acceleration of the baseball?
We can use Newton's second law to find the acceleration of the baseball. The mass of the baseball is 0.15kg, and the force applied on it is 250N. Therefore, we can rearrange the equation to solve for the acceleration (a = F / m).
a = 250N / 0.15kg
a ≈ 1666.67 m/s²
So, the acceleration of the baseball is approximately 1666.67 m/s².
C) What is the speed of the baseball at the end of the 0.2 seconds?
To find the speed of the baseball, we need to use the equation of motion: v = u + at, where v is the final velocity, u is the initial velocity (which we assume to be 0 since the ball starts from rest), a is the acceleration, and t is the time.
v = 0 + (1666.67 m/s²) * (0.2 s)
v ≈ 333.33 m/s
Therefore, the speed of the baseball at the end of the 0.2 seconds is approximately 333.33 m/s.