A ball is thrown horizontally from the top of a building 30.1 m high. The ball strikes the ground at a point 66.8 m from the base of the building.
The acceleration of gravity is 9.8 m/s2 . Find the time the ball is in motion. Answer in units of s
how long is it in the air?
66.8=1/2 g t^2 solve for t.
To find the time the ball is in motion, we can use the equation of motion for vertical motion, specifically the equation for time of flight:
t = sqrt(2h/g)
where t is the time of flight, h is the height of the building, and g is the acceleration due to gravity.
In this case, h = 30.1 m and g = 9.8 m/s^2.
Plugging in the values, we have:
t = sqrt(2 * 30.1 / 9.8)
≈ sqrt(60.2 / 9.8)
≈ sqrt(6.14)
Taking the square root, we find:
t ≈ 2.48 s
Therefore, the time the ball is in motion is approximately 2.48 seconds.