if 10 litres of a solution of na2co3 contains 21.2g of na2co3, what is its strength?
21.2 g Na2CO3 = ? moles. moles = grams/molar mass
Then M = moles/L soln.
Given, weight of na2co3(w)=21.2g
Volume of na2co3 solution (v)=10L
Strength (normality)=?
Now,
Normality=W/E*v=21.2/53*10=0.04N
To calculate the strength of the Na2CO3 solution, we need to determine the amount of Na2CO3 dissolved in each liter of the solution.
Given:
Volume of solution (V) = 10 liters
Mass of Na2CO3 dissolved (m) = 21.2 g
Step 1: Calculate the concentration of Na2CO3 in grams per liter (g/L).
Concentration (C) = mass/volume
C = m/V
C = 21.2 g/10 L
C = 2.12 g/L
Step 2: Convert the concentration to a percentage.
Percentage strength = (C/1) * 100
Percentage strength = (2.12 g/L / 1) * 100
Percentage strength = 212%
Therefore, the strength of the Na2CO3 solution is 212%.
To determine the strength of the solution, we need to calculate the concentration of sodium carbonate (Na2CO3). The concentration can be calculated using the formula:
Concentration (in g/L) = Mass of solute (in g) / Volume of solution (in L)
Given the following information:
- Mass of sodium carbonate (Na2CO3) = 21.2 g
- Volume of solution = 10 L
Substituting the values into the formula:
Concentration (in g/L) = 21.2 g / 10 L
Now, we can calculate the concentration:
Concentration (in g/L) = 2.12 g/L
Therefore, the strength of the solution is 2.12 g/L.