A 0.82 kg physics book with dimensions of 32.4 cm by 20.1 cm is on a table.
What force does the book apply to the
table?
Answer in units of N
Weight = M*g,
regardless of dimensions.
g is the accleration of gravity, which you should have learned about by now.
To find the force that the book applies to the table, we can use the formula:
Force = mass × acceleration
The acceleration due to gravity is approximately 9.8 m/s².
First, let's convert the dimensions of the book from centimeters to meters:
Length = 32.4 cm = 0.324 m
Width = 20.1 cm = 0.201 m
Next, let's calculate the area of the book:
Area = Length × Width
Area = 0.324 m × 0.201 m
Area = 0.065124 m²
Now, let's calculate the force:
Force = mass × acceleration
Force = 0.82 kg × 9.8 m/s²
Force ≈ 8.036 N
Therefore, the force that the book applies to the table is approximately 8.036 N.
To find the force that the book applies to the table, we need to use the Newton's second law of motion, which states that force (F) is equal to the product of mass (m) and acceleration (a). In this case, the book is not accelerating, so the acceleration is zero.
First, let's find the weight of the book, because the weight is the force exerted by an object due to gravity. The weight can be calculated using the formula: weight (W) = mass (m) × gravitational acceleration (g).
The mass of the book is given as 0.82 kg. The gravitational acceleration can be approximated as 9.8 m/s^2.
So, the weight of the book can be calculated as:
W = 0.82 kg × 9.8 m/s^2
W ≈ 8.036 N
Therefore, the book applies a force of approximately 8.036 Newtons to the table.