You have made scores of 81, 76, 82 on Three quizzes. What is the least you can make on this quiz to have an average of at least 80?
I tried solving this problem, but them got lost. How do i solve it?
81+76+82=239
239/3=79.6
81+81+76+82=320
320/4=80
your missing number or the grade you need to get is an 81 at least. if you make an 81. you will have an 80 as you average grade
Thank You so much :)
81+76+82=239
239/3=79.6
81+81+76+82=320
320/4=80
your missing number or the grade you need to get is an 81 at least. if you make an 81. you will have an 80 as you average grade
To solve this problem, you need to find the minimum score you can achieve on the fourth quiz that will result in an average score of at least 80.
First, let's calculate the current average score:
(81 + 76 + 82) / 3 = 79.67 (rounded to two decimal places)
To find the minimum score needed, let's assign a variable, "x," to represent the score on the fourth quiz.
Now, we can set up an equation to represent the average score:
(81 + 76 + 82 + x) / 4 ≥ 80
To solve this inequality, we can multiply both sides of the equation by 4 to eliminate the division:
(81 + 76 + 82 + x) ≥ 320
Next, we combine the known scores:
239 + x ≥ 320
Then, subtract 239 from both sides of the equation to isolate the variable:
x ≥ 320 - 239
Simplifying further:
x ≥ 81
Therefore, the minimum score you need to achieve on the fourth quiz to have an average of at least 80 is 81.