The sum of two numbers is 144. Double the first number minus thrice the second number is equal to 63. Determine the two numbers

one of them i 81

63 To determine the two numbers, we can set up a system of equations using the given information.

Let's assume the first number is represented by 'x' and the second number is represented by 'y'.

From the given information, we have two equations:

1. The sum of two numbers is 144:
x + y = 144

2. Double the first number minus thrice the second number is equal to 63:
2x - 3y = 63

Now we have a system of equations. To solve it, we can use a method such as substitution or elimination.

Let's solve using the substitution method:
From the first equation, we know that x = 144 - y. We can substitute this value of x into the second equation:

2(144 - y) - 3y = 63

Simplify the equation:

288 - 2y - 3y = 63
288 - 5y = 63

Rearrange the equation:

-5y = 63 - 288
-5y = -225

Divide both sides by -5:

y = -225 / -5
y = 45

Now that we have the value of y, we can substitute it back into the first equation to find x:

x + 45 = 144

Subtract 45 from both sides:

x = 144 - 45
x = 99

Therefore, the two numbers are x = 99 and y = 45.