A tile is 38 cm long and the space between the tiles is 0.8. How many tiles are required to build a floor 5.82 m long?
You know, 7 minutes is not a real long time to get impatient for an answer.
Take a look at what you need.
The first tile uses up 38cm.
Each other tile uses up 38.8 cm, including the grout.
So, the total length of n tiles is 38 + 38.8(n-1)
So, solve this equation for n to see how many tiles to use. Round up toi a whole number.
38 + 38.8n = 582
Oops: 38 + 38.8(n-1) = 582
To find out how many tiles are required to build a floor 5.82 m long, we need to calculate the number of tiles required by dividing the total length of the floor by the length of each tile plus the spacing between them.
First, let's convert the length of the tile and the spacing into the same unit, either centimeters (cm) or meters (m).
Given:
Length of a tile = 38 cm
Spacing between the tiles = 0.8 cm
To convert the length of the tile and spacing into meters, we divide each value by 100:
Length of the tile in meters = 38 cm / 100 = 0.38 m
Spacing between the tiles in meters = 0.8 cm / 100 = 0.008 m
Now let's calculate the number of tiles required:
Total floor length = 5.82 m
Number of tiles required = Total floor length / (Length of the tile + Spacing between tiles)
Number of tiles required = 5.82 m / (0.38 m + 0.008 m)
Calculating this equation will give us the number of tiles required to build the floor.