The principal component of many kidney stones is calcium oxalate,CaC2O4. A kidney stone recovered from a typical patient contains 8.50×10^20 formula units of calcium oxalate.

How many moles of CaC2O4 are present in this kidney stone?

Oh, kidney stones, those little calcium oxalate surprises! Let's calculate the number of moles in this stone, shall we?

The molar mass of calcium oxalate (CaC2O4) is the sum of the atomic masses of its constituent elements:
Ca (40.08 g/mol) + C (12.01 g/mol) + 2O (16.00 g/mol) + 4O (16.00 g/mol) = 128.08 g/mol

Now, we can use this molar mass to determine the number of moles in the kidney stone using Avogadro's number (6.022 x 10^23).

moles = formula units / Avogadro's number

moles = 8.50 x 10^20 / 6.022 x 10^23

And after some mathematical magic, we find that the number of moles of CaC2O4 in this kidney stone is approximately... *drumroll*... 0.141 moles!

So, there you have it! This kidney stone contains roughly 0.141 moles of calcium oxalate. Hope that answers your question without causing any (additional) pain!

To find the number of moles of CaC2O4 present in the kidney stone, we need to use Avogadro's number.

Avogadro's number, denoted as Na, is equal to 6.022 × 10^23 formula units/mol.

Given:
Number of formula units of calcium oxalate (CaC2O4) = 8.50 × 10^20 formula units

Using the formula:
Number of moles = Number of formula units / Avogadro's number

Number of moles = (8.50 × 10^20 formula units) / (6.022 × 10^23 formula units/mol)

Calculating the number of moles:
Number of moles = 0.0141 moles

Therefore, there are approximately 0.0141 moles of CaC2O4 present in this kidney stone.

To determine the number of moles of CaC2O4 present in the kidney stone, we need to use Avogadro's number and the formula unit of CaC2O4.

1. Start by determining the molar mass of CaC2O4:
- Calcium (Ca) has a molar mass of 40.08 g/mol.
- Carbon (C) has a molar mass of 12.01 g/mol.
- Oxygen (O) has a molar mass of 16.00 g/mol.
The molar mass of CaC2O4 can be calculated as follows:
(1 * 40.08 g/mol) + (2 * 12.01 g/mol) + (4 * 16.00 g/mol) = 128.09 g/mol

2. Next, use Avogadro's number to convert the number of formula units to moles:
Avogadro's number is approximately 6.022 × 10^23 formula units per mole.
Divide the given number of formula units (8.50 × 10^20 formula units) by Avogadro's number:
(8.50 × 10^20 formula units) / (6.022 × 10^23 formula units/mol) ≈ 1.41 × 10^(-3) mol

Therefore, there are approximately 1.41 × 10^(-3) moles of CaC2O4 present in this kidney stone.

1 mole = 6.02x1023

so, how many moles in the kidney stone?

8.5x1020/6.02x1023
= 1.41x10-3 = 0.00141