The larger of two consecutive integers is 10 more than 4 times the smaller. Find the integers.

How about

x+1 = 4x+10
3x = -9
x = -3

The two numbers are -3, -2

-2 = 4(-3) + 10

Steve your amazing

To find the two consecutive integers, let's assume the smaller integer is represented by the variable x.

According to the problem, the larger integer is 10 more than 4 times the smaller. This can be expressed as:

Larger integer = 4 * smaller integer + 10

Now we can substitute x for the smaller integer in the equation:

Larger integer = 4x + 10

Since the integers are consecutive, we know that the larger integer is exactly one more than the smaller integer. So, we can express the larger integer as x + 1.

Setting the expressions for the larger integer equal to each other, we have:

x + 1 = 4x + 10

To solve for x, we can subtract x from both sides of the equation:

1 = 3x + 10

Then, we can subtract 10 from both sides of the equation:

-9 = 3x

Finally, divide both sides of the equation by 3 to isolate x:

x = -9/3

Simplifying, we find:

x = -3

Now that we have the value of x, we can find the larger integer by substituting it back into the equation for the larger integer:

Larger integer = 4x + 10
Larger integer = 4 * -3 + 10
Larger integer = -12 + 10
Larger integer = -2

Therefore, the smaller integer is -3 and the larger integer is -2.

I don't see how that could be possible for two consectutive integers.

I don't see how that could be possible for two consectutive integers.

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