What is the net force acting on a 25-N freely falling object? What is the net force when the object encounters 15N of air resistance? When it falls fast enough to encounter 25N of air resistance?
F_net values are:
a) M*g = 25 N
b) M*g -15 N = 10 N
c) 25 - 25 = 0
Well, if the object is freely falling without any air resistance, then the net force would simply be its weight. So in this case, the net force would be 25 N.
Now, when the object encounters 15N of air resistance, the net force would be the difference between the weight and the air resistance. But let me tell you, air resistance can be quite the party pooper! So the net force would be the weight minus the air resistance, which means the net force would be 10N (25N - 15N).
Now, if the falling object decides to pick up the pace and encounters 25N of air resistance, well, let's just say the air resistance is putting up a good fight! The net force would be the weight minus the air resistance, which means the net force would be a big fat zero! (25N - 25N = 0N). Yup, that's right, the object would experience no net force because the air resistance is equal to its weight. It's like a cosmic balancing act!
To determine the net force acting on a freely falling object, you need to consider the forces acting on it.
1. When the object is freely falling without any air resistance, the net force is equal to its weight. The weight of the object can be calculated using the formula:
Net force = Weight = mass × acceleration due to gravity
Given that the weight of the object is 25 N, you need to divide this value by the acceleration due to gravity, which is approximately 9.8 m/s²:
Net force = 25 N ÷ 9.8 m/s² ≈ 2.55 N
Therefore, the net force on the object when freely falling without air resistance is approximately 2.55 N.
2. When the object encounters 15 N of air resistance, the net force can be calculated by subtracting the air resistance from the weight:
Net force = Weight - Air resistance
Net force = 25 N - 15 N = 10 N
Therefore, the net force on the object, when encountering 15 N of air resistance, is 10 N.
3. When the object falls fast enough to encounter 25 N of air resistance, the air resistance becomes equal to its weight. In this case, the net force on the object would be zero since the weight and air resistance balance each other out.
Net force = Weight - Air resistance
Net force = 25 N - 25 N = 0 N
Therefore, the net force on the object, when encountering 25 N of air resistance, is zero.
To calculate the net force acting on a freely falling object, we need to consider the gravitational force (weight) and any additional forces acting on it.
1. When there is no air resistance:
The only force acting on the object is its weight, which is given by the formula: F = m * g,
where F is the force, m is the mass of the object, and g is the acceleration due to gravity (approximately 9.8 m/s² on Earth).
Given that the weight (force) of the freely falling object is 25 N, we can calculate the mass by rearranging the formula:
m = F / g,
m = 25 N / 9.8 m/s² ≈ 2.55 kg.
Therefore, the net force acting on the object is also 25 N.
2. When the object encounters 15 N of air resistance:
Now, we need to consider the force of air resistance acting against the object's motion. The net force will be the difference between the weight and the air resistance force:
Net force = weight - air resistance.
By subtracting the air resistance of 15 N from the weight of 25 N, we get:
Net force = 25 N - 15 N = 10 N.
3. When the object encounters 25 N of air resistance:
Similar to the previous case, we subtract the air resistance force of 25 N from the weight of 25 N:
Net force = 25 N - 25 N = 0 N.
In this scenario, the net force becomes zero, meaning that the air resistance force exactly balances the weight, resulting in no acceleration. The object would reach a terminal velocity and continue falling at a constant speed.
Remember that net force is the vector sum of all forces acting on an object. When there is no acceleration, the net force is 0, indicating a state of equilibrium.