When the valve between the 2.00-L bulb, in which the gas pressure is 2.00 atm, and the 3.00-L bulb, in which the gas pressure is 4.50 atm, is opened, what will be the final pressure in the two bulbs? Assume the temperature remains constan
What pressure (in atm) would be exerted by 76 g of fluorine gas in a 1.50-liter vessel at -37oC
To find the final pressure in the two bulbs when the valve is opened, we can use the combined gas law. The combined gas law states that the ratio of the product of pressure and volume to the temperature is constant for a given amount of gas.
The formula for the combined gas law is:
(P1 * V1) / T1 = (P2 * V2) / T2
where:
P1 = initial pressure in bulb 1
V1 = initial volume in bulb 1
P2 = initial pressure in bulb 2
V2 = initial volume in bulb 2
T1 = initial temperature
T2 = final temperature
In this case, we are assuming the temperature remains constant, so T1 = T2.
Let's plug in the values we know:
P1 = 2.00 atm
V1 = 2.00 L
P2 = 4.50 atm
V2 = 3.00 L
(P1 * V1) / T = (P2 * V2) / T
(2.00 atm * 2.00 L) / T = (4.50 atm * 3.00 L) / T
4.00 atm*L = 13.50 atm*L
Dividing both sides by L:
4.00 atm = 13.50 atm
Therefore, the final pressure in both bulbs will be 13.50 atm when the valve is opened and the temperature remains constant.
To find the final pressure in the two bulbs, you can use the combined gas law, which states:
(P1 * V1) / T1 = (P2 * V2) / T2
In this case, the temperature remains constant, so T1 = T2. Let's assume T1 = T2 = T.
We have the following information:
P1 = 2.00 atm (pressure in the 2.00-L bulb)
V1 = 2.00 L (volume of the 2.00-L bulb)
P2 = 4.50 atm (pressure in the 3.00-L bulb)
V2 = 3.00 L (volume of the 3.00-L bulb)
Plugging in the values into the combined gas law equation, we get:
(2.00 atm * 2.00 L) / T = (4.50 atm * 3.00 L) / T
Now, let's solve for the final pressure (P) in the two bulbs.
Multiplying both sides of the equation by T, we have:
(2.00 atm * 2.00 L) = (4.50 atm * 3.00 L)
Simplifying the equation, we get:
4.00 atm*L = 13.50 atm*L
Finally, dividing both sides of the equation by the total volume of the two bulbs (2.00 L + 3.00 L = 5.00 L) to get the final pressure:
4.00 atm*L / 5.00 L = 0.80 atm
Therefore, the final pressure in the two bulbs will be 0.80 atm.
One way to do this is to use PV = nRT and solve for n = PV/RT.
Calculate n for one bulb and n for the other bulb, add the two and calculate P from PV = nRT using the sum of the bulbs for n. I get 3.5. What do you use for R and T. Whatever values are convenient because they end up canceling.
Another way is to look at the equation for n = PV/RT. Since T is a constant and R is a constant, we can just leave them out of the equation.
Then n1 = PV = 2*2 = 4
n2 = 3.5*4 = 13.5
Total n = 17.5
17.5 = PV. V is the total of 3L + 2L = 5L. Solve for P.