Calculate the number of grams of oxygen required to convert 58.0g of glucose to CO2 and H2O?
To calculate the number of grams of oxygen required to convert 58.0g of glucose to CO2 and H2O, we need to consider the balanced chemical equation for the combustion of glucose.
The balanced equation is:
C6H12O6 + 6O2 → 6CO2 + 6H2O
From the equation, we can see that 1 mole of glucose reacts with 6 moles of oxygen to produce 6 moles of carbon dioxide and 6 moles of water.
To find the number of moles of glucose, we need to use the molar mass of glucose, which is 180.18 g/mol.
Number of moles of glucose = mass of glucose / molar mass of glucose
Number of moles of glucose = 58.0g / 180.18 g/mol
Simplifying the above calculation will give us the moles of glucose
Moles of glucose = 0.321 mol
Since the balanced equation tells us that 1 mole of glucose reacts with 6 moles of oxygen, we can calculate the moles of oxygen required.
Moles of oxygen = Moles of glucose * 6
Moles of oxygen = 0.321 mol * 6
Now, to find the mass of oxygen, we need to use the molar mass of oxygen, which is 32.00 g/mol.
Mass of oxygen = Moles of oxygen * molar mass of oxygen
Mass of oxygen = (0.321 mol * 6) * 32.00 g/mol
Executing the above calculations will give us the answer.
Hence, the number of grams of oxygen required to convert 58.0g of glucose to CO2 and H2O is approximately 61.57g.