A boy starts at rest and slides down a frictionless slide as in the figure below. The bottom of the track is a height h above the ground. The boy then leaves the track horizontally, striking the ground a distance d as shown. Using energy methods, determine the initial height H of the boy in terms of h and d.

Correction

h + (d^2)/4h

h + (d^2)/h

How are you getting the answers? Pls explain.

mg/(H-h)=1/2mv^2

H=h+(d^2)/h

H=h+(d^2)/h

\frac{\left(d^2+4h^2\right)}{4h}