calculate the mass percent of sand, sodium chloride and copper(ll) sulfate in a sample that yields: mass of sample= 14.088g, mass of sand=0.2255g, mass of copper(ll)oxide = 0.1994g (assume 100% yield for each of the copper(ll) reactions)
CuSO4(aq) + 2NaOH(aq) --> Cu(OH)2(s) + Na2SO4(aq)
Cu(OH)2---> CuO(s) +H2O
Would you please check your post. You need to explain what you're doing. Where did the NaCl come from? What did you do with the excess NaOH?
To calculate the mass percent of each component in the sample, we will divide the mass of each component by the mass of the sample, and then multiply by 100 to express the result as a percentage.
1. Calculate the mass of copper(II) sulfate:
We know that copper(II) sulfate is converted to copper(II) oxide (CuO) through the reaction:
Cu(OH)2 --> CuO + H2O
Since the reaction assumes 100% yield, the mass of copper(II) sulfate (CuSO4) is the same as the mass of copper(II) oxide (CuO).
Therefore, the mass of copper(II) sulfate is 0.1994g.
2. Calculate the mass of sodium chloride (NaCl):
We know that the reaction between copper(II) sulfate and sodium hydroxide (NaOH) only produces copper(II) hydroxide (Cu(OH)2) and sodium sulfate (Na2SO4).
The mass of sodium chloride (NaCl) is not mentioned in the reaction equation, so we assume there is no NaCl present in the sample.
3. Calculate the mass of sand:
The mass of sand is given as 0.2255g.
4. Calculate the mass percent:
Mass percent of copper(II) sulfate = (mass of copper(II) sulfate / mass of sample) * 100%
= (0.1994g / 14.088g) * 100%
≈ 1.416%
Mass percent of sodium chloride = (mass of sodium chloride / mass of sample) * 100%
= (0g / 14.088g) * 100%
= 0%
Mass percent of sand = (mass of sand / mass of sample) * 100%
= (0.2255g / 14.088g) * 100%
≈ 1.602%
Therefore, the mass percent of copper(II) sulfate in the sample is approximately 1.416%, the mass percent of sodium chloride is 0%, and the mass percent of sand is approximately 1.602%.