A student found that there are 115 drops of glacial acetic acid in 2.00 mL. Calculate the number of drops of glacial acetic acid, HC2H3O2 required to make 225 mL of 0.1 M acetic acid solution
12937.5
To calculate the number of drops of glacial acetic acid required to make a certain volume and concentration of acetic acid solution, we need to follow these steps:
1. Find the number of drops per mL: In this case, you have been given that there are 115 drops in 2.00 mL. So, we can find the number of drops in 1 mL by dividing 115 by 2.00:
Number of drops per mL = 115 drops / 2.00 mL = 57.5 drops/mL (rounded to the nearest whole number)
2. Calculate the number of drops required for the desired volume of acetic acid solution: In this case, we need to find the number of drops required to make 225 mL of 0.1 M acetic acid solution.
To calculate this, we need to know the concentration of glacial acetic acid. Glacial acetic acid is usually approximately 99.5% pure. So, we can assume that it has a concentration of 99.5%.
Now, to find the number of drops required, we can use the following formula:
Number of drops = (Volume of solution in mL) × (Concentration of solution in M) / (Concentration of glacial acetic acid in %) × (Number of drops per mL)
Number of drops = (225 mL) × (0.1 M) / (99.5%) × (57.5 drops/mL)
Calculate the number of drops using this formula, and round your answer to the nearest whole number.
By following these steps, you can calculate the number of drops of glacial acetic acid required to make a 225 mL, 0.1 M acetic acid solution.
(115dps/2mL) = (x dps/225mL)
Solve for x.