Calculate the concentrations of all species present in a 0.32 M solution of ethylammonium chloride (C2H5NH3Cl).
....C2H5NH3^+ + HOH ==> C2H4NH3 + H3O^+
init...0.32...............0..........0
change..-x................x.........x
equil..0.32-x..............x.........x
Ka = (Kw/Kb) = (x)(x)/(0.32-x)
Solve for x and that will allow you to calculate all species except Cl^- and that is 0.32M.
To calculate the concentrations of all species present in a solution of ethylammonium chloride (C2H5NH3Cl), we need to consider the dissociation of the compound in water. Ethylammonium chloride is a salt that ionizes in water to form ethylammonium cations (C2H5NH3+) and chloride anions (Cl-).
The balanced chemical equation for the dissociation of ethylammonium chloride in water is:
C2H5NH3Cl (s) ⇌ C2H5NH3+ (aq) + Cl- (aq)
In a 0.32 M solution of ethylammonium chloride, the initial concentration of the compound is 0.32 M. Since ethylammonium chloride completely ionizes, the concentration of the ethylammonium cations (C2H5NH3+) and chloride anions (Cl-) will be the same as the initial concentration of the ethylammonium chloride.
Therefore, in a 0.32 M solution of ethylammonium chloride:
- The concentration of ethylammonium cations (C2H5NH3+) is 0.32 M.
- The concentration of chloride anions (Cl-) is 0.32 M.
To calculate the concentrations of all species present in a solution of ethylammonium chloride (C2H5NH3Cl), we first need to understand the dissociation of this compound in water.
Ethylammonium chloride (C2H5NH3Cl) is a salt composed of the ethylammonium cation (C2H5NH3+) and the chloride anion (Cl-). When this compound dissolves in water, it dissociates into its constituent ions:
C2H5NH3Cl(s) → C2H5NH3+(aq) + Cl-(aq)
Given that we have a 0.32 M (molar) solution of ethylammonium chloride, we can assume that the concentration of the ethylammonium cation (C2H5NH3+) will also be 0.32 M, as the compound dissociates in a 1:1 ratio.
Thus, the concentration of C2H5NH3+ in the solution is 0.32 M.
Since ethylammonium chloride fully dissociates into C2H5NH3+ and Cl- ions, the concentration of the chloride anion (Cl-) will also be 0.32 M.
Therefore, the concentrations of all species in the 0.32 M solution of ethylammonium chloride are as follows:
- Concentration of ethylammonium cation (C2H5NH3+): 0.32 M
- Concentration of chloride anion (Cl-): 0.32 M