3/4 part of circle with 2 lines 0.7 m . find its perimeter.

If the 2 lines are radii, the perimeter is

(3/4)*(2 pi R)+(2 R)

= 3.5*pi*R

= 7.697 m

I forgot how to add

(3/4)*(2 pi R)+(2 R)

=(2 + 1.5pi)R = 6.712R = 4.699 m

0.7M

To find the perimeter of the 3/4 part of a circle with 2 lines measuring 0.7 m, you can follow these steps:

1. Determine the radius of the circle: Since we have two lines forming an angle of 3/4 of a circle, we can find the angle that each line makes by multiplying 3/4 by 360 degrees. So, the angle between the two lines is 270 degrees.
2. Use the angle and the length of one of the lines to find the radius. Since we know the angle is 270 degrees and one line measures 0.7 m, we can use trigonometry. Divide the length (0.7 m) by the sine of half the angle (270 degrees / 2 = 135 degrees). Using the formula: radius = length / (2 * sin(angle/2)), we have radius = 0.7 m / (2 * sin(135 degrees / 2)).
3. Calculate the circumference: The circumference of a circle is given by the formula C = 2πr, where r is the radius. Plug in the radius value you calculated in step 2 into the formula: C = 2 * π * radius.
4. Calculate the perimeter of the 3/4 part of the circle: The perimeter will be equal to 3/4 times the circumference, as we are only dealing with a fractional part of the circle. Multiply the circumference by 3/4 to get the perimeter.

So, by following these steps, you can find the perimeter of the 3/4 part of the circle with 2 lines measuring 0.7 m.