Help me!;/

1) my numerator is 6 less than my denominator. I am equivalent to 3/4.
2)my denominator is 5 more than twice my numerator. I am equivalent to 1/3.
3)the gcf of my numerator and denominator is 3. I am equivalent to 2/5.
4)the gcf of my numerator and denominator is 5.i am equivalent to 4/6.
5)my numerator and denominator are prime numbers. My numerator is one less than my denominator.
6)my numerator and denominator are prime numbers. The sum of my numerator and denominator is 24.
7) my numerator is divisible by 3. My denominator is divisible by 5. My denominator is 4 less than twice my numerator.
8) my numerator is divisible by 3. My denominator is divisible by 5. My denominator is 3 more than twice my numerator.
9) my numerator is a one_digit prime number. My denominator is a one_digit composite number. I am equivalent to 8/32.
10) my numerator is a prime number. The gcf of my numerator and denominator is 2. I am equivalent to 1/5.
Help please!!!(;

I will give you help on some of these.

1. x/(x+6) = 3/4

Multiply both sides by x+6 and 4.

4x = 3x + 18

x = 18, the x+6 = 24

18/24 = 3/4

2. x/(2x+5) = 1/3 (Use same process as in #1.)

5. Are 2 and 3 both prime numbers?

6. What two prime numbers add to 24? Go up the scale of primes to find if 24 minus that number gives you another prime.

I hope this gives you a start.

The GCf of my numerator and denominator is 3. I am equivalent to 2/5

i don't kow sorry

Sure! I can help you with these problems. Let's go through each one together:

1) Let's represent the numerator as "x" and the denominator as "y". According to the information given, we can write the equation as x = y - 6, and also x/y = 3/4. To solve this, we substitute the value of x from the first equation into the second equation. So, (y - 6)/y = 3/4. Cross multiplying, we get 4(y - 6) = 3y. Solve for y, and once you find the value of y, substitute it back into the equation to find x.

2) Similar to the first problem, let's represent the numerator as "x" and the denominator as "y". We know that y = 2x + 5, and also x/y = 1/3. Substitute the value of y into the equation from the first relationship, and solve for x. Once you find x, substitute it back into the equation to find y.

3) Since the greatest common factor (GCF) of the numerator and denominator is 3, we can write the numerator as 3a and the denominator as 3b. According to the given information, 3a/3b = 2/5. Cross multiplying, we get 5(3a) = 2(3b). Solve for a and b, and once you find their values, substitute them back into the equation to find the numerator and denominator.

4) Similar to the previous problem, let's write the numerator and denominator as 5a and 5b respectively (since the GCF is 5). According to the information, 5a/5b = 4/6. Cross multiplying, we get 6(5a) = 4(5b). Solve for a and b, and substitute them back into the equation to find the numerator and denominator.

5) The numerator is one less than the denominator. Let's represent the numerator as x and the denominator as (x+1) (since the numerator is one less than the denominator). According to the given information, x/(x+1) = 3/4. Cross multiplying, we get 4x = 3(x+1). Solve for x, and once you find its value, substitute it back into the equation to find the numerator and denominator.

6) The sum of the numerator and denominator is 24. Let's represent the numerator as x and the denominator as (24-x) (since their sum is 24). According to the information, x/(24-x) = 2/5. Cross multiplying, we get 5x = 2(24-x). Solve for x, and once you find its value, substitute it back into the equation to find the numerator and denominator.

7) The numerator is divisible by 3, the denominator is divisible by 5, and the denominator is 4 less than twice the numerator. Let the numerator be 3a and the denominator be 5b, where a and b are integers. According to the given information, (3a)/(5b) = 4-2a. Cross multiplying, we get 3a = (4-2a)(5b). Solve for a and substitute it into the equation to find b. Once you have the values for a and b, substitute them back into the equation to find the numerator and denominator.

8) Similar to the previous problem, let's represent the numerator as 3a and the denominator as 5b, where a and b are integers. According to the given information, (3a)/(5b) = 2a+3. Cross multiplying, we get 3a = (2a+3)(5b). Solve for a and substitute it into the equation to find b. Once you have the values for a and b, substitute them back into the equation to find the numerator and denominator.

9) The numerator is a one-digit prime number, and the denominator is a one-digit composite number. The prime numbers between 1 and 9 are 2, 3, 5, and 7. The composite numbers between 1 and 9 are 4, 6, 8, and 9. Check each pair of numbers to see if their ratio is equivalent to 8/32.

10) The numerator is a prime number, and the GCF of the numerator and denominator is 2. Start by listing the prime numbers: 2, 3, 5, 7, 11, 13, 17, 19, 23... Check each prime number to see if its ratio with a denominator (2, 4, 6, 8, 10, etc.) is equivalent to 1/5.

I hope this helps you in solving these problems! If you have any more questions, feel free to ask.