at 20 degree C the speed of sound in air is 344 m/s. This is 1.117 m/s slower than the speed of sound in water.
write and solve an equation to find the speed of sound in water.
i started writeing this but im not sure how to do this:
344 - s = 344
im not sure how to do this?
can you check : is this righ:
s- 1.117 = 3.44
s-1.117 + 1.117 = 3.44 +1.117
s-0 = 4.557
s= 4.557
4.557 - 1.117 = 3.44
3.44 = 3.44
I'm sorry, Marko, but I never took physics and my math skills stop about middle school level.
ok but this is in algebra mathword problem about physic
No, that is all wrong.
I suggest you look again at the way I did it.
To solve this problem, we need to set up an equation and solve for the speed of sound in water.
Let's denote the speed of sound in water as "s" (in m/s), and the speed of sound in air as 344 m/s. We know from the given information that the speed of sound in water is 1.117 m/s faster than the speed in air.
So, our equation will be:
s = 344 + 1.117
To solve this equation, we simply add 1.117 to 344:
s = 345.117 m/s
Therefore, the speed of sound in water is approximately 345.117 m/s.
You must reside in the part of the world that uses a comma as a decimal point, and vice versa. The speed of sound is water is 1,117 m/s faster than it is in air. (One thousand, one hundred seventeen)
If s is the speed in water,
s = 344 + 1117.
s = 1461 m/s
sorry i mistyped
so can i write it out like this:
s - 1,117 344
s - 1,117 + 1,117 = 344 + 1,117
s-0 = 1461
s=1,461
check; s - 1117 = 344
1461 - 1117 = 344