A block of mass 2kg placed on a long frictionless horizontal table is pulled horizontally by a constant force F. It is found to move 10 m in the first two seconds find the magnitude of F
It is frictjonless so accelerates at a constant rate, a. They must want you to assume it starts from rest. The acceleration rate a is then given by
10 = (a/2)t^2 = 2a
a = 5 m/s^2
Now use F = M a for the force.
F = 10 N
To find the magnitude of the force, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration:
F_net = m * a
In this case, the block is moving horizontally, so we can assume the acceleration is constant. Let's denote the acceleration as "a".
Given:
Mass of the block (m) = 2 kg
Distance traveled (d) = 10 m
Time taken (t) = 2 s
We can find the acceleration using the formula:
a = (2 * d) / (t^2)
Substituting the values:
a = (2 * 10) / (2^2) = 20 / 4 = 5 m/s^2
Now that we know the acceleration, we can find the net force acting on the block using the formula mentioned earlier:
F_net = m * a
F = m * a
Substituting the values:
F = 2 kg * 5 m/s^2 = 10 N
Therefore, the magnitude of the force F is 10 Newtons.