what forward force must the ground apply to the foot of a 60.0 kg person to result in an acceleration of 1.00m/s^2
To find the forward force that the ground must apply to the foot of a person, we can use Newton's second law of motion, which states that the force (F) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a). The formula for Newton's second law is F = m * a.
Given:
Mass of the person (m) = 60.0 kg
Acceleration (a) = 1.00 m/s^2
We can substitute these values into the formula and solve for the force (F):
F = m * a
F = 60.0 kg * 1.00 m/s^2
F = 60.0 N
Therefore, the ground must apply a forward force of 60.0 Newtons to the foot of the person in order to result in an acceleration of 1.00 m/s^2.