What exposure will a radiology technologist receive when exposed for 10 minutes at 4 meters from a source with intensity of 100 mR/min at 1 meter?
To determine the exposure a radiology technologist will receive when exposed to a source of radiation, we can use the inverse square law and the concept of exposure rate.
The inverse square law states that the radiation intensity is inversely proportional to the square of the distance from the source. Mathematically, it can be expressed as:
I1 / I2 = (D2 / D1)^2
where I1 and I2 are the radiation intensities at distances D1 and D2, respectively.
In this case, the radiation intensity at 1 meter is given as 100 mR/min. The technologist is located at a distance of 4 meters from the source. Therefore, we can calculate the radiation intensity at 4 meters using the inverse square law:
(100 mR/min) / I2 = (1 m / 4 m)^2
Simplifying the equation:
I2 = (100 mR/min) / (1/16)
I2 = 1600 mR/min
So, the radiation intensity at a distance of 4 meters from the source is 1600 mR/min.
Now, to calculate the exposure received by the technologist in 10 minutes, we multiply the radiation intensity by the exposure time:
Exposure = Radiation Intensity * Time
Exposure = 1600 mR/min * 10 min
Exposure = 16000 mR
Therefore, the technologist will receive an exposure of 16000 milliroentgens (mR) when exposed for 10 minutes at 4 meters from a source with an intensity of 100 mR/min at 1 meter.