The density of dry air measured at 25 degrees celsius is 1.19 x 10 to the negative 3 g/cm cubed. What is the volume of 50.0g of air?
mass = volume x density
50.0 = v x 1.19E-3
Dry air has a density of 1.29g/L (@ 25 degrees Celsius & 1 atm of pressure). How many liters would 500.g of this air occupy?
To find the volume of 50.0g of air, we can use the formula:
Density = Mass / Volume
First, let's convert the given density from grams per cubic centimeter (g/cm³) to grams per milliliter (g/mL) since we are working with the mass in grams:
1 g/cm³ = 1 g/mL
Now, we can rewrite the given density of dry air as 1.19 x 10^(-3) g/mL.
Next, rearrange the formula to solve for volume:
Volume = Mass / Density
Substituting the given mass of 50.0g and the density of 1.19 x 10^(-3) g/mL into the equation:
Volume = 50.0g / (1.19 x 10^(-3) g/mL)
Now, we need to convert the volume from milliliters to cubic centimeters since they are equivalent:
1 mL = 1 cm³
So the final calculation will be:
Volume = 50.0g / (1.19 x 10^(-3) g/cm³)
Now, let's plug in the values and calculate the volume.