Calculate the molarity of NaI in a soultion obtained by adding 5.0 mL of 0.2 M NaI to a mixture of 5.0 mL of 0.2 M K2SO4,5.0 mL K2S2O8, 4.0 mL of H2O and 1.0 mL of Starch
0.2M x (5.0mL/20mL) = ??
To calculate the molarity of NaI in the solution, we need to determine the moles of NaI and the total volume of the solution.
First, let's find the moles of NaI:
Moles of NaI = Volume of NaI (in liters) × Molarity of NaI
Given that the volume of NaI is 5.0 mL and the molarity is 0.2 M, we need to convert the volume to liters:
Volume of NaI (in liters) = 5.0 mL × (1 L / 1000 mL) = 0.005 L
Now we can find the moles of NaI:
Moles of NaI = 0.005 L × 0.2 M = 0.001 mol
Next, let's calculate the total volume of the solution. Since we're adding various components, we'll add up the volumes:
Total volume = Volume of NaI + Volume of K2SO4 + Volume of K2S2O8 + Volume of H2O + Volume of Starch
Total volume = 5.0 mL + 5.0 mL + 5.0 mL + 4.0 mL + 1.0 mL = 20.0 mL
We also need to convert the total volume to liters:
Total volume (in liters) = 20.0 mL × (1 L / 1000 mL) = 0.02 L
Finally, we can calculate the molarity of NaI:
Molarity of NaI = Moles of NaI / Total volume (in liters)
Molarity of NaI = 0.001 mol / 0.02 L = 0.05 M
Therefore, the molarity of NaI in the solution is 0.05 M.