in the diagram below of triangle abc, de is a midsegment of triangle abc, de=7, ab=10, and bc=13.find the perimeter

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  1. Well, we don't have a diagram, but that won't stop us in this case. A midsegment of a triangle is parallel to one of the sides, and half its length.

    Since de=7 is not half of ab=10, nor of bd=13, then that means that it must be half of ac. So, ac=14, and the perimeter is

    p = 10 + 13 + 14 = 37

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  2. joel

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  3. Perimeter is the total of all triangle,so we have a triangle with side 10,13and 14(half of DE ).Now we just have to add this side 10+13+14=37
    37 is the perimeter of a triangle

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