what is the moment of interia of a solid cylinder of radius R=0.0950m thickness t=0.015m total mass M=3.565kg? show your work

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  1. The moment of inertia of a solid cylinder or disc is (1/2) M R^2, and does not depend upon the thickness.

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  2. Moment of Ineria= 1/2 MR^2 = 1/2 (3.565kg)(0.0950m)^2= 0.016 kg.m^2

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