Find the x and y intercepts of f(x)=x^2-x-6.
y=f(x)=x^2-x-6
The y-intercept is the value of y when x=0.
Substitute x=0 in the above equation to find the y-intercept.
The x-intercept is to find the roots of the equation, when y=0, or
f(x)=x^2-x-6=0
By factoring f(x) into
f(x)=(x-3)(x+2)
you should be able readily find the two zeroes of f(x).
If you need further help, post again.
well i know the x-intercept is (3,-2)
but i can seem to understand y intercept. I thought it would be (0,0) but it was wrong
The y-intercept is where the graph crosses the y-axis, that is, where x=0.
In this case, f(0) = 0 - 0 - 6 = -6, so the y-intercept is (0,-6)
Also, there are two x-intercepts: (3,0) and (-2,0). They are the points where the graph crosses the x-axis, not just the x-values.
Thank you!!
To find the x-intercepts of a function, we need to find the values of x where the function intersects the x-axis. In other words, we need to find the values of x for which f(x) = 0.
To find the x-intercepts of the function f(x) = x^2 - x - 6, we set the function equal to 0:
x^2 - x - 6 = 0
Now we can factor this quadratic equation or use the quadratic formula to solve for x.
We can factor the equation as follows:
(x - 3)(x + 2) = 0
Setting each factor equal to 0, we get:
x - 3 = 0 or x + 2 = 0
Solving for x in each case, we find:
x = 3 or x = -2
So the x-intercepts of the function are x = 3 and x = -2.
To find the y-intercept of a function, we need to find the value of y when x = 0. In other words, we substitute 0 for x in the function and solve for y.
In this case, we have the function f(x) = x^2 - x - 6. Substituting x = 0, we get:
f(0) = 0^2 - 0 - 6 = -6
So the y-intercept is y = -6.
Therefore, the x-intercepts of the function f(x) = x^2 - x - 6 are x = 3 and x = -2, and the y-intercept is y = -6.