# College Algebra

A ferris wheel has a diameter of 320 feet and the bottom of the Ferris wheel is 9 feet above the ground. Find the equation of the wheel if the origin is placed on the ground directly below the center of the wheel.

1. a circle of radius r with center at (h,k) is

(x-h)^2 + (y-k)^2 = r^2

so, the center is at (0,9+160)

x^2 + (y-169)^2 = 160^2

posted by Steve
2. 44779

posted by g c

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