An apple falls off a tree branch located 35 meters off the ground. How many seconds does it take to hit the ground?

We can use the equation for free fall:

h = (1/2)gt^2, where h is the height (35 meters), g is the acceleration due to gravity (9.8 m/s²), and t is the time in seconds.

Rearranging the equation to solve for t:
t = √(2h/g)

Plugging in the given height and acceleration:
t = √(2*35/9.8)
t ≈ 2.67 seconds

It takes approximately 2.67 seconds for the apple to hit the ground.

To find out how many seconds it takes for the apple to hit the ground, we can use the formula for the time it takes for an object to fall from a certain height, ignoring air resistance.

The formula is:

t = √(2h/g)

where:
t is the time it takes for the object to fall,
h is the height from which it falls, and
g is the acceleration due to gravity, which is approximately 9.8 m/s² on Earth.

In this case, the height from which the apple falls is 35 meters, so we can substitute the values into the formula:

t = √(2 * 35 / 9.8)

t ≈ √(70 / 9.8)

We can now calculate the square root to find the approximate value of t:

t ≈ √7.142857142857143

t ≈ 2.67 seconds (rounded to two decimal places)

Therefore, it takes approximately 2.67 seconds for the apple to hit the ground.