Question

A lift is used to carry boxes to the top floor of a hotel 20m high.A total weight of 100kg of boxes was caried up in 20second.If the useful output of the engine driving the lift mechanism is 1.2 kilowatt.calculate the efficiency of the engine of the lift mechanism.

Answer 1

Fb = mg = 100kg * 9.8N/kg = 980N. = Force of the boxes.

Po = Fb*d / t = 980 * 20 / 20 = 980W. =
Power output.

Eff. = (Po / Pi)* 100%,
Eff. = (980 / 1200) * 100% = 81.67%.

Answer 2

Where did 9.8N come about

Answer 3

9.80N = 1kg

Answer 4

I don't understand the solving

Answer 5

Pls I don't understand ur solving

Answer 6

Thanks I understand

Answer 7

Interesting