Balance:
NH3 + [Cd(NH3)4] > Cd2+ + NH4+
You are missing something.
NH3 + [Cd(NH3)4]2+ > Cd2+ + NH4+
Is that what you mean?
Then it will never balance.
On the left, for every Cd, you have +2 charge. On the right, for every Cd, you have a +2 charge AND a + charge for each N.
Somehow, something has to be reduced for this to happen. Charges just can't be manufactured.
So I guess I don't understand what you mean.
The chemical equation you provided is NH3 + [Cd(NH3)4] -> Cd2+ + NH4+. To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.
Let's start by balancing the nitrogen (N) atoms. There is one nitrogen atom on the left side and one on the right side, so nitrogen is already balanced.
Now, let's balance the hydrogen (H) atoms. There are three hydrogen atoms on the left side (1 from NH3 and 2 from [Cd(NH3)4]) and four hydrogen atoms on the right side (4 from NH4+). To balance the hydrogen atoms, we can add another hydrogen molecule to the left side:
NH3 + [Cd(NH3)4] + H2 -> Cd2+ + NH4+
Next, let's balance the cadmium (Cd) atoms. There is one cadmium atom on the left side and one on the right side, so cadmium is balanced.
Finally, let's balance the charge. The charges on the left side are neutral (0) since NH3 and [Cd(NH3)4] have no charge. On the right side, Cd2+ has a charge of +2 and NH4+ has a charge of +1. To balance the charges, we can add two ammonium ions (NH4+) to the left side:
NH3 + [Cd(NH3)4] + H2 + 2NH4+ -> Cd2+ + 2NH4+
Now the equation is balanced with equal numbers of each atom and a consistent charge on both sides:
NH3 + [Cd(NH3)4] + H2 + 2NH4+ -> Cd2+ + 2NH4+
To balance the given chemical equation:
NH3 + [Cd(NH3)4] → Cd2+ + NH4+
Step 1: Count the atoms of each element on both sides of the equation to see which elements are unbalanced.
On the left side:
- Nitrogen (N): 1 atom from NH3
- Hydrogen (H): 4 atoms from [Cd(NH3)4] and 4 atoms from NH3
- Cadmium (Cd): 1 atom from [Cd(NH3)4]
On the right side:
- Cadmium (Cd): 1 atom
Step 2: Start by balancing the elements that appear in only one compound on each side. In this case, we will start with cadmium (Cd).
On the left side, there is 1 cadmium atom, so we need 1 cadmium atom on the right side as well.
NH3 + [Cd(NH3)4] → Cd2+ + NH4+
Step 3: Next, balance the nitrogen (N) atoms. On the left side, there is 1 nitrogen atom from NH3. On the right side, there is 1 nitrogen atom from NH4+.
NH3 + [Cd(NH3)4] → Cd2+ + NH4+
Step 4: Balance the hydrogen (H) atoms. On the left side, there are 4 hydrogen atoms from [Cd(NH3)4] and 3 hydrogen atoms from NH3, totaling 7 hydrogen atoms. On the right side, there are 4 hydrogen atoms from NH4+.
To balance the hydrogen atoms, we need to add 3 more hydrogen atoms on the right side.
NH3 + [Cd(NH3)4] → Cd2+ + 3NH4+
Step 5: The equation is now balanced for all elements. Finally, check that the total charge is balanced. On the left side, the total charge is 0 (0 charge from NH3 and [Cd(NH3)4]). On the right side, the total charge is +2 from Cd2+ and +3 from 3NH4+, totaling +5.
To balance the total charge, we need to add 5 electrons to the left side.
NH3 + [Cd(NH3)4] + 5e- → Cd2+ + 3NH4+
The final balanced equation is:
NH3 + [Cd(NH3)4] + 5e- → Cd2+ + 3NH4+