math

farmer fred had chickens and cows on his farm. he knows that together there are 108 legs and 30 heads. how many of each type of animal does he have?

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  1. c chickens have 2c legs
    m cows have 4m legs

    c+m = 30
    2c + 4m = 108

    multiply the top equation by two, and subtract

    2c + 2m = 60
    2c + 4m = 108

    2m = 48
    m = 24
    c = 6

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