THE WIDTH OF A RECTANGLE IS TWO-FIFTH OF THE LENGTH . WHAT ARE THE DIMENSION IF THE PERIMETER IS 112 FEET?
W = Width
L = Lentgh
P = Perimeter
W = ( 2 / 5 ) L
P = 2 W + 2 H
112 = 2 ( 2 / 5 ) L + 2 L
( Remark : 2 L = ( 10 / 5 ) L )
112 = ( 4 / 5 ) L + ( 10 / 5 ) L
112 = ( 14 / 5 ) L Multiply both sides with 5
112 * 5 = 14 L
560 = 14 L Diwide both sides with 14
560 / 14 = L
L = 40 ft
W = ( 2 / 5 ) L
W = ( 2 * 40 ) / 5
W = 80 / 5
W = 16 ft
P = 2W + 2 H
P = 2 * 16 + 2 * 40
P = 32 + 80
P = 112 ft