mrs.wheelbarrow weasel is less than 100 years old.her year of birth is divisible by 23 and 17, as well as by one other prime number less than 30.when was mrs.wheelbarrow weasel born?if she was still alive,how old would she be this year?(2007)
Since her year of birth must be divisible by both 23 and 17, it must be divisible by 391, (23 x 17)
Since she is less than 100 she must have been born in the 19hundreds.
So her birth year must be a multiple of 361, it is easy to just try a few multipliers by 361 and I got 1955 = 5*391
Notice that 1955 is only divisible by the primes 5,17, and 23
So if she was born in 1955, then in 2007 she would be 52
"So her birth year must be a multiple of 361, it is easy to just try a few multipliers by 361 and I got 1955 = 5*391 "
should have been:
So her birth year must be a multiple of 391, it is easy to just try a few multipliers by 391 and I got 1955 = 5*391
To find out when Mrs. Wheelbarrow Weasel was born, we need to find a prime number less than 30 that divides her birth year. Let's examine the prime numbers less than 30:
2, 3, 5, 7, 11, 13, 17, 19, 23, 29
We know that her birth year is divisible by both 23 and 17. We need to find one prime number from the above list that also divides her birth year.
The only prime numbers that satisfy this condition are 23, 17, and 2. Since 23 and 17 are already accounted for, we can conclude that Mrs. Wheelbarrow Weasel was born in a year divisible by 2.
Now, let's find the multiple of 23, 17, and 2:
23 x 17 x 2 = 782
Therefore, Mrs. Wheelbarrow Weasel was born in the year 782.
To find out how old she would be in 2007, subtract her birth year (782) from 2007:
2007 - 782 = 1225
If Mrs. Wheelbarrow Weasel were still alive, she would be 1225 years old in the year 2007.