calculate horizontal force that must be applied to 1kg to make 6ounce to make it accelerat on horizontal friction three hour table dropped with same acceleration it would have if it and feel freely

To calculate the horizontal force required to make a 1 kg object accelerate on a horizontal frictionless surface with the same acceleration it would have if it were freely falling, we can use Newton's second law of motion.

First, let's convert the mass of the object from 1 kg to ounces. There are approximately 35.274 ounces in 1 kg.

1 kg = 35.274 ounces

Now, we need to determine the acceleration of the object. Since the object is freely falling, it will experience the acceleration due to gravity, which is approximately 9.8 m/s^2.

Next, we need to convert the acceleration from m/s^2 to the desired unit, which is ounces per hour. To do this, we can use unit conversions:

1 m = 39.37 inches (approx.)
1 hour = 3600 seconds

The conversion factor for changing meters to inches is approximately 39.37. Therefore, the conversion factor for changing m/s^2 to ounces per hour would be:

(39.37 inches/m) x (1 ounce/28.35 grams) x (1000 grams/1 kg) x (3600 seconds/1 hour) = X ounces/hour

Now, we can substitute the values into the equation:

acceleration = (9.8 m/s^2) x [(39.37 inches/m) x (1 ounce/28.35 grams) x (1000 grams/1 kg) x (3600 seconds/1 hour)]

Simplifying the equation, we get:

acceleration = (9.8 m/s^2) x 4.21 ounces/hour

acceleration = 41.058 ounces/hour

Now that we have determined the acceleration, we can calculate the force required to achieve this acceleration. Using Newton's second law of motion,

Force = mass x acceleration

Mass = 6 ounces (given)

Force = (6 ounces) x (41.058 ounces/hour)

Force = 246.35 ounces^2/hour

Therefore, the horizontal force that must be applied to the 1 kg object to make it accelerate on a horizontal frictionless surface with the same acceleration it would have if it were freely falling is approximately 246.35 ounces^2/hour.