MATH

i really need help on this question!! I need to solve it using a system of two equations, the question says that an automobile radiator contains 16L of antifreeze and water. this mixture is 30%antifreeze. how much of this mixture should be drained and replaced with pure antifreeze so that there will be 50% antifreeze?

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asked by Laura
  1. Yes, you had best do this. It is January!

    the initial condition has
    .3 * 16 = 4.8 L antif
    .7 * 16 = 11.2 L H2O
    we take away x liters of mix
    that is we take away .3 x L antif
    and take way .7 x L H2O
    then we add the same x liters antif

    the result must be 8 L of antif
    and 8 L of H2O
    so
    4.8 L antif - .3 x L antif + x L antif = 8 L antif

    4.8 - .3 x + x = 8
    .7 x = 3.2
    x = 4.57
    Now check that carefully. I am sleepy.

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    posted by Damon

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