write the equation of the line tangent to the curve y= 3x^3- 2x at the point where x=2
y'= 9x^2-2 which is the slope,
y'=34 at x=2
y= mx+b
y=34x+b
now at x=2, y= 3*8-4=22
22=34*2+b solve for b, and you have the equation of the tangent.
y'=34 at x=2
y= mx+b
y=34x+b
now at x=2, y= 3*8-4=22
22=34*2+b solve for b, and you have the equation of the tangent.