calculate how many mL of 6M HCL are needed to prepare 100mL HCL solution with a concentration of ~1M?
Use the dilution formula which is
mL1 x M1 = mL2 x M2
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To calculate how many mL of 6M HCl are needed to prepare a 100 mL HCl solution with a concentration of approximately 1M, you can use the formula:
C1V1 = C2V2
Where:
C1 = concentration of initial solution
V1 = volume of initial solution
C2 = concentration of final solution
V2 = volume of final solution
In this case, we are given that the initial concentration (C1) is 6M, the initial volume (V1) is unknown (we'll solve for it), the final concentration (C2) is 1M, and the final volume (V2) is 100 mL.
Plugging these values into the formula, we have:
(6M)(V1) = (1M)(100mL)
Simplifying this equation, we get:
6V1 = 100
Now, we can solve for V1:
V1 = 100 / 6
V1 = 16.67 mL
Therefore, you would need approximately 16.67 mL of 6M HCl to prepare a 100 mL HCl solution with a concentration of approximately 1M.