Can someone help me balance this i tried and didn't succeeded.
Fe2O3 + CO --> Fe + CO2
Fe2O3 + 3CO --> 2Fe + 3CO2
This one is difficult, took me about 10 minutes, but it's pretty simple in a way that you just plug in number and do trial and errors...
Thanks Jake
Of course! I can help you balance this chemical equation. Balancing chemical equations involves making sure that there are an equal number of atoms of each element on both sides of the equation.
Let's start by counting the atoms of each element on both sides:
Fe:
On the left side, there are 2 Fe atoms in Fe2O3.
On the right side, there is 1 Fe atom in Fe.
O:
On the left side, there are 3 O atoms in Fe2O3.
On the right side, there are 2 O atoms in CO2.
C:
On the left side, there is 1 C atom in CO.
On the right side, there is 1 C atom in CO2.
Now, let's try to balance the equation by adjusting the coefficients in front of each compound:
Fe2O3 + CO --> Fe + CO2
Since there are already 2 Fe atoms on the left side, we can balance the Fe by placing a coefficient of 2 in front of Fe:
Fe2O3 + CO --> 2 Fe + CO2
Now, let's balance the O. Since there are 3 O atoms in Fe2O3 and only 2 O atoms in CO2, we can balance the O by placing a coefficient of 3/2 in front of CO2:
Fe2O3 + CO --> 2 Fe + (3/2) CO2
To eliminate the fraction, we can multiply the entire equation by 2 to get rid of the denominators:
2(Fe2O3) + 2(CO) --> 4(Fe) + 3(CO2)
Now, the equation is balanced with an equal number of atoms on both sides.
Final balanced equation:
2 Fe2O3 + 2 CO --> 4 Fe + 3 CO2
I hope this helps you balance the equation! If you have any further questions, feel free to ask.