A Pratt and whitney PW4000 turbofan engine is able to provide a maximum thrust of 2.49 x 100000 N.A Boeing 747-400 airliner has four of these engines. If its mass is 2.72 x 100000 kg, what is its acceleration?

That will depend upon the aerodynamic drag, which was not provided.

If the drag were zero, the acceleration would be F/m =
4*2.49*10^5/2.72*10^5 m/s^2
= 3.67 m/s^2

Zero drag is a fair approximation at low speeds, e.g. takeoff.

That will depend upon the aerodynamic drag, which was not provided.

If the drag were zero, the acceleration would be F/m =
4*2.49*10^5/2.72*10^5 m/s^2
= 3.67 m/s^2

Zero drag is a fair approximation at low speeds, e.g. takeoff.

To find the acceleration of the Boeing 747-400 airliner, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.

Given:
Thrust (F) = 2.49 x 100,000 N
Mass (m) = 2.72 x 100,000 kg

Since the aircraft has four engines, the total thrust provided by all the engines is 4 x 2.49 x 100,000 N = 9.96 x 100,000 N.

Using Newton's second law, we can rearrange the equation to solve for acceleration (a):

F = ma

Rearranging the equation, we have:

a = F / m

Now, plug in the values for force (F) and mass (m):

a = (9.96 x 100,000 N) / (2.72 x 100,000 kg)

The units of "N" and "kg" cancel out, leaving us with the unit of acceleration, which is meters per second squared (m/s²).

a = 9.96 / 2.72 = 3.66 m/s²

Therefore, the acceleration of the Boeing 747-400 airliner is approximately 3.66 m/s².

To find the acceleration of a Boeing 747-400 airliner, we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass times its acceleration (F = ma).

Given information:
- Maximum thrust (force) of one Pratt and Whitney PW4000 turbofan engine: 2.49 x 100000 N
- Number of engines on the Boeing 747-400: 4
- Mass of the Boeing 747-400 airliner: 2.72 x 100000 kg

Step 1: Calculate the total thrust generated by all four engines:
Total thrust = Thrust per engine x Number of engines
Total thrust = (2.49 x 100000 N) x 4
Total thrust = 9.96 x 100000 N

Step 2: Substitute the values into the formula F = ma:
9.96 x 100000 N = (2.72 x 100000 kg) x a

Step 3: Solve for acceleration (a):
a = (9.96 x 100000 N) / (2.72 x 100000 kg)
a = 3.6618 m/s^2

Therefore, the acceleration of the Boeing 747-400 airliner is approximately 3.66 m/s^2.