The Republic of Singapore Air Force uses the AIM-9 Sidewinder air-to-air missile which has a mass of 85.6kg. If the missile can accelerate from 300m/s to 700m/s in 6 seconds, what is the average force exerted on the missile?

velocity changed from 300km/s to 700km/s = (400km/s)/(6s) = 66.67km/s^2

F = ma = 85.6 * 66.67 = 5707N

To find the average force exerted on the missile, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a):

F = m * a

Given:
Mass of the missile (m) = 85.6 kg
Initial velocity (u) = 300 m/s
Final velocity (v) = 700 m/s
Time taken (t) = 6 seconds

We need to find the acceleration (a) first. The formula to calculate acceleration is:

a = (v - u) / t

Substituting the given values:

a = (700 m/s - 300 m/s) / 6 s
a = 400 m/s / 6 s
a = 66.67 m/s^2 (rounded to two decimal places)

Now, we can calculate the average force (F) exerted on the missile using the formula mentioned earlier:

F = m * a
F = 85.6 kg * 66.67 m/s^2
F ≈ 5700.11 N

Therefore, the average force exerted on the missile is approximately 5700.11 Newtons.

To calculate the average force exerted on the missile, we can use Newton's second law of motion which states that force (F) is equal to the mass (m) of an object multiplied by its acceleration (a).

F = m * a

In this case, the mass of the missile is given as 85.6 kg, and we need to calculate the acceleration to find the force. To calculate acceleration, we can use the equation:

a = (final velocity - initial velocity) / time

Given that the initial velocity (u) is 300m/s, the final velocity (v) is 700m/s, and the time (t) is 6 seconds, we can substitute these values into the equation to find the acceleration:

a = (700 - 300) / 6

a = 400 / 6

a ≈ 66.67 m/s^2

Now that we have the acceleration, we can substitute it into the force equation along with the given mass of the missile:

F = 85.6 kg * 66.67 m/s^2

F ≈ 5706.12 N

Therefore, the average force exerted on the missile is approximately 5706.12 Newtons.