A 0.267kg ball is thrown straight up from 2.20m above the ground. Its initial vertical speed is 9.20m/s. A short time later, it hits the ground. Calculate the total work done by the force of gravity during that time.
Hi,so you need help,well i need help with my subjects anyway,but i help,so it says a 0.267kg ball is thrown straight up from 2.20m above the ground,its initial vertical speed is 9.20m/s,a moment later it hits the ground,you have to calculate the total work done by the force of gravity,so you calculate the ball's weight,the meter above the ground,and i think the initial vertical speed altogether,and you get this,i don't think we are at the same age,but do you know how to calculate all of this work together,if you don't,how about asking someone you know that is close to you archi,or you could search in the internet to help me,i got my answers from that,do you have a smart calculator,you know you need to study hard to know the answer,u need to figure out ideas to help u solve this problem,ask,read a book that helps,search in the internet,review the questions,do that,and don't waste your time doing something else!thats all i can help anyway.i hope this will help you learn more.
Holy smoke, Losa! Please learn some of the standard conventions of typing!!
~ a space after every period and comma
~ a capital letter at the beginning of every sentence
~ hit the Enter key twice at the end of each paragraph
When you run everything together like this it's VERY difficult to read.
http://www.typingweb.com/typingtutor/
The answer is zero, since it returns to the same ground elevation at the same speed.
To calculate the total work done by the force of gravity on the ball, we need to determine the change in potential energy of the ball as it falls from its initial height to the ground.
First, let's find the initial potential energy of the ball. The potential energy (PE) is given by the formula PE = mgh, where m is the mass of the ball (0.267 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the initial height (2.20 m):
PE initial = (0.267 kg) * (9.8 m/s^2) * (2.20 m) = 5.78 J
Next, we'll find the final potential energy of the ball when it hits the ground. Since the ball is at ground level, the height (h) is zero, so the potential energy (PE final) is also zero.
To calculate the work done by gravity, we can use the equation W = PE final - PE initial. Substituting the values we found earlier, we get:
W = 0 J - 5.78 J = -5.78 J
The negative sign indicates that the work done by gravity is in the opposite direction to the displacement of the ball. In this case, since the ball is falling downwards, the work done by gravity is negative.
Therefore, the total work done by the force of gravity during that time is -5.78 Joules.