The ordered pairs in each exercise are for the same direct variation.
Find the missing value.
(3,2) and (6,y)
I don't know how to find the missing value ..
yes, 4
To find the missing value in a direct variation, you can use the concept of ratios. In a direct variation, the ratio between the x-values and the y-values remains constant.
In this case, the given ordered pairs are (3,2) and (6,y). Since these pairs represent a direct variation, we can set up a ratio using the x-values and the y-values:
x1 / y1 = x2 / y2
Substituting the given values from the ordered pairs:
3 / 2 = 6 / y
To solve for the missing value, we can cross-multiply:
3y = 12
Now, divide both sides of the equation by 3 to isolate the variable:
y = 4
Therefore, the missing value is y = 4.
y=4?
well.....yes 4 but what if it was
(5,9), (15,y)
Assuming that "direct variation" means that the second number of each pair is a certain fixed ratio to the first number, then
3/2 = 6/y
3y = 12
y = ?