this is my last one i couldn't find the answer please help ???
Two workers pull horizontally on a heavy box, but one pulls twice as hard as the other. The larger pull is directed at 25.0 o west of north, and the resultant of these two pulls is 400.0 N directly northward.
Use vector components to find the magnitude of each of these pulls. Assume that the smaller pull has a component directed to the north.
Enter your answers numerically separated by a comma. =170.34 N
Use vector components to find the direction of the smaller pull. Assume that the smaller pull has a component directed to the north ? ..............................o east of north
A football coach sits on a sled while two of his players build their strength by dragging the sled across the field with ropes. The friction force on the sled is 1200 N and the angle between the two ropes is 15.0 ∘. How hard must each player pull to drag the coach at a steady 1.70 m/s ? Assume both players pull with the same force.
sorry i don't know either. im also looking for the answer
To solve this problem, we can use vector addition and trigonometry.
First, let's assign variables to the magnitudes of the two pulls. Let's call the smaller pull P and the larger pull 2P.
We know that the resultant of the two pulls is 400.0 N directed northward. This means that the y-component of the larger pull is equal to the magnitude of the resultant: 2P sin(25°) = 400.0 N.
Now, we can solve for P. Rearranging the equation, we have P = 400.0 N / (2 * sin(25°)).
Calculating this value numerically, we find that P is approximately 170.34 N.
To find the direction of the smaller pull, we need to use trigonometry. We know that the larger pull is directed at 25.0° west of north.
Since the smaller pull has a component directed to the north, the direction of the smaller pull is the complement to the direction of the larger pull (90° - 25°).
The smaller pull is directed 65° east of north.