A particle moving with uniform acceleration in a straight line was first observed to be moving at 4.5 m/s. After 10 sec, it was moving at 6.8 m/s. What is its acceleration?

Divide the velocity change (+2.3 m/s) by the time interval (10 s).

0.23 m/s^2

To calculate the acceleration of the particle, we can use the formula:

acceleration (a) = change in velocity (Δv) / time interval (Δt)

Given:

Initial velocity (u) = 4.5 m/s
Final velocity (v) = 6.8 m/s
Time interval (Δt) = 10 sec

We can calculate the change in velocity (Δv) by subtracting the initial velocity from the final velocity:

Δv = v - u

Substituting the given values:

Δv = 6.8 m/s - 4.5 m/s
Δv = 2.3 m/s

Now we can calculate the acceleration:

a = Δv / Δt

Substituting the values:

a = 2.3 m/s / 10 sec
a = 0.23 m/s^2

Therefore, the acceleration of the particle is 0.23 m/s^2.

To find the acceleration of the particle, we can use the equation of motion that relates the initial velocity (u), final velocity (v), acceleration (a), and time (t):

v = u + at

Given data:
Initial velocity, u = 4.5 m/s
Final velocity, v = 6.8 m/s
Time, t = 10 s

We can rearrange the equation to solve for acceleration:

a = (v - u) / t

Substituting the given values:

a = (6.8 m/s - 4.5 m/s) / 10 s

Next, we can calculate the difference in velocity:

a = 2.3 m/s / 10 s

Finally, we can divide the difference in velocity by the time to find the acceleration:

a = 0.23 m/s²

Therefore, the acceleration of the particle is 0.23 m/s².